3x-12=x^2-4x+3

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Solution for 3x-12=x^2-4x+3 equation: 



3x-12=x^2-4x+3

We move all terms to the left:

3x-12-(x^2-4x+3)=0

We get rid of parentheses

-x^2+3x+4x-3-12=0

We add all the numbers together, and all the variables

-1x^2+7x-15=0

a = -1; b = 7; c = -15;
Δ = b2-4ac
Δ = 72-4·(-1)·(-15)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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